Hello friends, welcome to Fullonstudy. Today we are going to discuss another important post i.e. Zeeman splitting of D1 & D2 lines.
Let us consider the Zeeman splitting of resonance lines D1 & D2 of sodium lines.
These lines arises from the transition 2P1/2 —–> 2S1/2 and. 2P3/2 ——–>2S1/2.
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The splitting of these terms may be displayed as :
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Applying the selection rules :
ΔMj = 0 , ±1 ( but Mj= 0 <—/—->Mj= 0 if ΔJ= 0 )
We obtain four Zeeman components for the D1 line and six components for the D2 line.
The components corresponding to Mj,=0 are polarised with electric vectors
perpendicular to the field (σ-components).
perpendicular to the field (σ-components).
The intensities of the Zeeman components are governed by the following rules :
(i) The sum of all transitions starting from any initial Zeeman level is equal to sum of all transition starting from any other level having the same n and I values.
(ii) The sum of all transitions arriving at any Zeeman level is equals to sum of all transitions arriving at any other level having the same n and I values.
The relative intensities are indicated by the heights of the lines drawn at the bottom of the fig. 2 above.
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