Hello friends, welcome to Fullonstudy. Today we are going to discuss another important post i.e. Zeeman splitting of D1 & D2 lines.

Let us consider the Zeeman splitting of resonance lines D1 & D2 of sodium lines.

These lines arises from the transition** 2P1/2 —–> 2S1/2 and. 2P3/2 ——–>2S1/2.**

The splitting of these terms may be displayed as :

Applying the selection rules :

*ΔMj = 0 , ±1 ( but Mj= 0 <—/—->Mj= 0 if ΔJ= 0 )*We obtain four Zeeman components for the D1 line and six components for the D2 line.

The components corresponding to Mj,=0 are polarised with electric vectors

perpendicular to the field (σ-components).

perpendicular to the field (σ-components).

The intensities of the Zeeman components are governed by the following rules :

(

**i**) The sum of all transitions starting from any initial Zeeman level is equal to sum of all transition starting from any other level having the same n and I values.**(ii**) The sum of all transitions arriving at any Zeeman level is equals to sum of all transitions arriving at any other level having the same n and I values.

The relative intensities are indicated by the heights of the lines drawn at the bottom of the fig. 2 above.

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